M1V1 + M2V2 = M3V3
(0.445 mol/L) (2.00 L) = 0.890 moles
(x) (3.88 L) = moles HCl in unknown solution
(0.974 mol/L) (5.88 L) = 5.73 moles
(4.49g CuCl2) (1 mole CuCl2 / 134.45 grams) = 0.033395 moles CuCl2
(0.033395 moles CuCl2) / (0.0515 liters) = 0.648 M
125.6 g / 41.9 g/mol = 3.00 mol
3.00 mol in 1000 mL so 3 x (180/1000) = 0.54 mol in 180 mL
0.54 mol / 0.50 L = 1.08 mol/L = 1.08 M
0.350 mol / 0.150 L = 2.33 M
M1V1 + M2V2 = M3V3